(2x^2+3x-4)/(x+4)

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Solution for (2x^2+3x-4)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(2*x^2+3*x-4)/(x+4) = 0

2*x^2+3*x-4 = 0

2*x^2+3*x-4 = 0

DELTA = 3^2-(-4*2*4)

DELTA = 41

DELTA > 0

x = (41^(1/2)-3)/(2*2) or x = (-41^(1/2)-3)/(2*2)

x = (41^(1/2)-3)/4 or x = (-(41^(1/2)+3))/4

(x+(41^(1/2)+3)/4)*(x-((41^(1/2)-3)/4)) = 0

((x+(41^(1/2)+3)/4)*(x-((41^(1/2)-3)/4)))/(x+4) = 0

( x+(41^(1/2)+3)/4 )

x+(41^(1/2)+3)/4 = 0 // - (41^(1/2)+3)/4

x = -((41^(1/2)+3)/4)

( x-((41^(1/2)-3)/4) )

x-((41^(1/2)-3)/4) = 0 // + (41^(1/2)-3)/4

x = (41^(1/2)-3)/4

x in { -((41^(1/2)+3)/4), (41^(1/2)-3)/4 }

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